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PARABOLA
AXIS OF SYMMETRY
VERTEX
Range
x = ±7
x=-1/2 and x=3
2x2=-32
x2=-16
x=±4i
(x+3)2=25
√ both sides
x+3 = ±5
x=-3±5
x=-3+5=2 and x=-3-5=-8
x=2 and x = -8
(x-3)(x-8)
(x-12)(x+11)
(5x+2)(5x-2)
(2x+1)(x+11)
(3x-2)(x+5)
(-4,6)
y=(x-2)2-9
y = 2(x - 0.5)(x - 5)
or
y = 2(2x - 1)(x - 5)
Solve: 0=16x2-1
(1/4, 0) and (-1/4, 0)
By Vertex Formula:
x=-(-7)/(2*3)
7/6
or
1.1667
y≥-2
y=(x+4)(x+4)-1
y=x2+4x+4x+16-1
y=x2+8x+15
y=-(x2+10x-2x-20)
y=-(x2+8x-20)
y=-x2-8x+20
y+c=(x2 -10x+c) +21
Find c: 1/2(10)=5→52=25=c
y+25 = (x2-10x+25)+21
y+25=(x-5)2+21
subtract 25 from both sides
y=(x-5)2-4
From the vertex we know:
y=a(x-1)2-2
From the point we know x & y:
0=a(0-1)2-2
0=a(-1)2-2
0=1a-2
2=a
Put "a" in the equation
y=2(x-1)2-2